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8w^2-2w-15=0
a = 8; b = -2; c = -15;
Δ = b2-4ac
Δ = -22-4·8·(-15)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*8}=\frac{-20}{16} =-1+1/4 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*8}=\frac{24}{16} =1+1/2 $
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